| 摘要: | 在低成本、低反射與低透光率等考量下，彩色濾光片大部份廠商 仍然以鉻金屬或鉻氧化物作為黑框(Black Matrix)的材料。當製程失 敗，採用氫氧化鉀作為清理處理藥劑可以避免將黑框一併蝕去，該玻 璃基板上之材料可以直接蝕除至樹脂層，基板仍可再生使用。 彩色濾光片玻璃基板再生製程所產生的廢鹼氫氧基濃度高達約 2.7 M，導電度值亦多達57mS cm-1，本研究希望藉由電解-電透析法， 去除氫氧基濃度，並同時回收、同時合成氫氧化鉀及次氯酸鈉。 本實驗裝置為四隔室型，為Pt-Ti / (1)KCl(aq) / C / (2)KOH(aq) / A / (3)wastewater / C / (4)KOH(aq) / steel，A、C分別為離子交換膜Asahi AMV與Nafion NX982TX，KCl(aq)在陽極室循環，KOH(aq)在濃縮室陰 極室循環，廢水在淡化室循環，並在陽極室外接氯氣吸收槽，以吸收 所產生之氯氣，製造次氯酸鈉。 由實驗數據可得知，本系統影響εc、εv之主要因素為室2、3 與4 之濃度、流速、及電流密度。綜合以上分析，選取適當實驗條件， 操作3 小時，原廢液淡化效率66.97%，氫氧化鉀再生效率179.74% 及次氯酸鈉生成效率75.4%。 同時藉由無因次分析，可得電流效率和電壓效率與系統操作變因 有著無因次之關係： 對於電流效率： 一：淡化室濃度大於濃縮室與陰極室 0.216 30.015 4 0.005 30.043 0 0 0 0 0 3.375( ) ( ) ( ) ( ) c I C C u FC u C C u ε = − R2 = 0.963 二：淡化室濃度小於濃縮室與陰極室 0.181 30.017 4 0.091 3 0.036 0 0 0 0 0 3.850( ) ( ) ( ) ( ) c I C C u FC u C C u ε = − − R2 = 0.96 對於電壓效率： 一：淡化室濃度大於濃縮室與陰極室 1 1 0.677 0.030 ln v cell cell Id I E E ε κ κ − − = + + − − d R2 = 0.954 二：淡化室濃度小於濃縮室與陰極室 1 1 0.677 0.031ln v cell cell Id I E E ε κ κ − − = + + − − d R2 = 0.982 Low cost, low to reflect, under low printing opacity rate,etc. CF manufacturers of slide yet regard chromium metal or the chromium oxide as the dark frame (Black Matrix) Material. Potassium hydroxide as is it deal with drug can prevent from to clear up without Black Matrix frame, glass material can be recover. CF recover process make the produce oxyhydrogen base up to 2.7 M, conductivity up to 57mS cm-1 also, research by electrolysis - electrodialysis to get rid of oxyhydrogen, and at the same time, formate potassium hydroxide and chloric acid sodium. It is in experimental for four compartment, it is Pt-Ti / (1)KCl(aq) /C / (2) KOH(aq) /A / (3) wastewater / C / (4) KOH(aq) /Steel, A, C are membrane Asahi AMV and Nafion NX982TX of ion exchange respectively. By the experimental data, it is the concentration, flow velocity, and current density of room 2, 3 and 4 that this system influences . choose the proper experiment condition, operate for 3 hours, the original wastewater diluate 66.97% of current efficiency, 179.74% of recover efficiency of potassium hydroxide and chloric acid sodium 75.4% of efficiency. By the dimensionless groups of the operation variables, we can get 4 equations for current and voltage efficienies. For C3>C4 0 .2 1 6 30 .0 1 5 4 0 .0 0 5 30 .0 4 3 0 0 0 0 0 3 .3 7 5 ( ) ( ) ( ) ( ) c I C C u F C u C C u ε = − 1 1 0.677 0 .030 ln v cell cell Id I E E ε κ κ − − = + + − − d For C3<C4 0 .1 8 1 3 0 .0 1 7 4 0 .0 9 1 4 0 .0 3 6 0 0 0 0 0 3 .8 5 0 ( ) ( ) ( ) ( ) c I C C u F C u C C u ε = − − 1 1 0 .677 0 .031 ln v c e ll ce ll Id Id E E ε κ κ |
